Runner Times 681B12
1. **State the problem:** Runners D, E, and F ran a sprint with a combined time of 72 seconds. Runner D's time is half of E's time and one-third of F's time. We need to find how long each runner took.
2. **Define variables:** Let $t_E$ be the time for runner E. Then runner D's time $t_D = \frac{1}{2} t_E$ and runner F's time $t_F = 3 t_D$ (since $t_D = \frac{1}{3} t_F$ implies $t_F = 3 t_D$).
3. **Express all times in terms of $t_E$:** Since $t_D = \frac{1}{2} t_E$, then $t_F = 3 t_D = 3 \times \frac{1}{2} t_E = \frac{3}{2} t_E$.
4. **Write the equation for total time:**
$$t_D + t_E + t_F = 72$$
Substitute:
$$\frac{1}{2} t_E + t_E + \frac{3}{2} t_E = 72$$
5. **Simplify the equation:**
$$\left(\frac{1}{2} + 1 + \frac{3}{2}\right) t_E = 72$$
$$\left(\frac{1}{2} + \frac{2}{2} + \frac{3}{2}\right) t_E = 72$$
$$\frac{6}{2} t_E = 72$$
$$3 t_E = 72$$
6. **Solve for $t_E$:**
$$t_E = \frac{72}{3} = 24$$
7. **Find $t_D$ and $t_F$:**
$$t_D = \frac{1}{2} t_E = \frac{1}{2} \times 24 = 12$$
$$t_F = \frac{3}{2} t_E = \frac{3}{2} \times 24 = 36$$
**Final answer:**
Runner D took 12 seconds, runner E took 24 seconds, and runner F took 36 seconds.