1. The problem requires evaluating several square roots and cube roots. 2. Calculate each root: - $\sqrt{36} = 6$ since $6 \times 6 = 36$. - $\sqrt[3]{27} = 3$ because $3 \times 3 \times 3 = 27$. - $\sqrt{9} = 3$. - $2\pi$ is a constant expression (approx. $6.283$). - $\sqrt{5}$ is an irrational number approximately $2.236$. - Another $\sqrt{5}$ is also approximately $2.236$. - $\sqrt{8,100} = \sqrt{8100} = 90$ because $90 \times 90 = 8100$. - $\sqrt{10,000} = 100$ since $100 \times 100 = 10,000$. 3. Final answers: $$\sqrt{36} = 6,$$ $$\sqrt[3]{27} = 3,$$ $$\sqrt{9} = 3,$$ $$2\pi \approx 6.283,$$ $$\sqrt{5} \approx 2.236,$$ $$\sqrt{5} \approx 2.236,$$ $$\sqrt{8100} = 90,$$ $$\sqrt{10,000} = 100.$$