1. **State the problem:** A missionary mixes 3 kg of premium rice at 60 per kg with 2 kg of regular rice at 40 per kg. We want to find the cost per kilogram of the mixture. 2. **Define variables:** Let $x$ = kilograms of premium rice, $y$ = kilograms of regular rice, and $t$ = total cost per kilogram of the mixture. 3. **Write the system of equations:** - Total cost: $$60x + 40y = \text{total cost}$$ - Total weight: $$x + y = \text{total kilograms}$$ 4. **Use given values:** The missionary mixes 3 kg premium rice and 2 kg regular rice, so: - $$x = 3$$ - $$y = 2$$ 5. **Calculate the total cost:** $$\text{total cost} = 60(3) + 40(2) = 180 + 80 = 260$$ 6. **Calculate total weight:** $$x + y = 3 + 2 = 5 \, \text{kg}$$ 7. **Find cost per kilogram of the mixture:** $$t = \frac{\text{total cost}}{\text{total weight}} = \frac{260}{5} = 52$$ **Answer:** The mixture should cost 52 per kilogram.