1. **State the problem:** We want to find the smallest number of emergency relief kits that each contain exactly one bottle of water, one can of food, and one beef jerky protein pack, with nothing left over from the crates/boxes. 2. **Analyze the numbers given:** - Bottles of water come in crates of 30. - Cans of food come in cartons of 24. - Beef jerky protein packs come in boxes of 80. 3. **What is asked?** We want the smallest number $n$ such that $n$ is a multiple of 30, 24, and 80. 4. **Mathematical approach:** This means finding the Least Common Multiple (LCM) of 30, 24, and 80. 5. **Prime factorization:** - $30 = 2 \times 3 \times 5$ - $24 = 2^3 \times 3$ - $80 = 2^4 \times 5$ 6. **Find LCM:** Take the highest powers of each prime: - Highest power of 2: $2^4$ - Highest power of 3: $3^1$ - Highest power of 5: $5^1$ So, $$\text{LCM} = 2^4 \times 3 \times 5 = 16 \times 3 \times 5 = 240$$ 7. **Interpretation:** The smallest number of kits you can make with no leftover water, food, or jerky is **240**. **Final answer:** 240 kits