Subjects algebra

Relative Error

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Relative Error


1. The problem is to calculate the relative error for each pair of values $(x, y)$ given in the table. 2. Relative error is defined as: $$\text{Relative Error} = \frac{|x - y|}{|x|}$$ 3. Calculate the relative error for each pair: - For $x=14$, $y=13$: $$\frac{|14 - 13|}{14} = \frac{1}{14} \approx 0.0714$$ - For $x=25$, $y=20$: $$\frac{|25 - 20|}{25} = \frac{5}{25} = 0.2$$ - For $x=31$, $y=33$: $$\frac{|31 - 33|}{31} = \frac{2}{31} \approx 0.0645$$ - For $x=35$, $y=30$: $$\frac{|35 - 30|}{35} = \frac{5}{35} \approx 0.1429$$ - For $x=42$, $y=45$: $$\frac{|42 - 45|}{42} = \frac{3}{42} \approx 0.0714$$ - For $x=45$, $y=42$: $$\frac{|45 - 42|}{45} = \frac{3}{45} = 0.0667$$ - For $x=52$, $y=48$: $$\frac{|52 - 48|}{52} = \frac{4}{52} \approx 0.0769$$ - For $x=54$, $y=51$: $$\frac{|54 - 51|}{54} = \frac{3}{54} \approx 0.0556$$ - For $x=66$, $y=55$: $$\frac{|66 - 55|}{66} = \frac{11}{66} \approx 0.1667$$ - For $x=62$, $y=63$: $$\frac{|62 - 63|}{62} = \frac{1}{62} \approx 0.0161$$ 4. These values represent the relative error between the corresponding $x$ and $y$ values. Final relative errors: $$[0.0714, 0.2, 0.0645, 0.1429, 0.0714, 0.0667, 0.0769, 0.0556, 0.1667, 0.0161]$$