1. **State the problem:** We have a rectangle with a perimeter of 44 cm. The length ($L$) is 6 cm more than the width ($W$). We need to find the length. 2. **Formula for perimeter of a rectangle:** $$P = 2(L + W)$$ where $P$ is the perimeter, $L$ is the length, and $W$ is the width. 3. **Express length in terms of width:** $$L = W + 6$$ 4. **Substitute into the perimeter formula:** $$44 = 2((W + 6) + W)$$ 5. **Simplify inside the parentheses:** $$44 = 2(2W + 6)$$ 6. **Distribute the 2:** $$44 = 4W + 12$$ 7. **Isolate $W$:** $$44 - 12 = 4W$$ $$32 = 4W$$ 8. **Solve for $W$:** $$W = \frac{32}{4} = 8$$ 9. **Find $L$ using $L = W + 6$:** $$L = 8 + 6 = 14$$ 10. **Check the perimeter:** $$2(14 + 8) = 2(22) = 44$$ which matches the given perimeter. **Final answer:** The length is 14 cm. Note: The options given do not include 14 cm, so the correct length based on the problem is 14 cm, which is not listed.