Rectangle Dimensions 795Bc9
1. **State the problem:** We need to find the length and width of a rectangle where the length is three times the width, and the perimeter is 48 cm.
2. **Recall the formula for the perimeter of a rectangle:**
$$P = 2(\text{length} + \text{width})$$
3. **Assign variables:**
Let the width be $w$ cm.
Then the length is $3w$ cm.
4. **Write the perimeter equation using these variables:**
$$48 = 2(3w + w)$$
5. **Simplify inside the parentheses:**
$$48 = 2(4w)$$
$$48 = 8w$$
6. **Solve for $w$:**
$$w = \frac{48}{8} = 6$$
7. **Find the length:**
$$\text{length} = 3w = 3 \times 6 = 18$$
**Final answer:**
Length = 18 cm
Width = 6 cm