1. **State the problem:** Teerasiole is a rectangle where the length is 5 inches longer than the width. The perimeter is 34 inches. We need to find the dimensions (length and width). 2. **Define variables:** Let $w$ be the width of the rectangle in inches. Then the length $l = w + 5$ inches. 3. **Write the formula for perimeter of a rectangle:** $$P = 2l + 2w$$ where $P$ is the perimeter. 4. **Substitute the known values:** $$34 = 2(w + 5) + 2w$$ 5. **Simplify and solve for $w$:** $$34 = 2w + 10 + 2w$$ $$34 = 4w + 10$$ $$34 - 10 = 4w$$ $$24 = 4w$$ $$w = \frac{24}{4} = 6$$ 6. **Find the length $l$:** $$l = w + 5 = 6 + 5 = 11$$ 7. **Answer:** The width is 6 inches and the length is 11 inches.