Rational Linear Angles
1. Represent 7/5 and 4/5 on the number line.
- The fractions 7/5 and 4/5 are represented as points on the number line between 1 and 2.
- 4/5 is less than 1, approximately 0.8, so mark a point before 1.
- 7/5 is greater than 1, exactly 1.4, so mark a point after 1.
2. Express 3x = 7 in ax + by + c = 0 form and find a, b, c.
- Given equation: $$3x = 7$$
- Bring all terms to LHS: $$3x - 7 = 0$$
- Comparing with $$ax + by + c = 0$$, we get $$a=3$$, $$b=0$$, $$c=-7$$.
3. Find 3 rational numbers between 3 and 4 using mean method.
- Mean of 3 and 4 is $$\frac{3+4}{2} = \frac{7}{2} = 3.5$$.
- Now find means between 3 and 3.5:
- Mean of 3 and 3.5: $$\frac{3 + 3.5}{2} = 3.25$$.
- Means between 3.5 and 4:
- Mean of 3.5 and 4: $$\frac{3.5 + 4}{2} = 3.75$$.
- So three rational numbers between 3 and 4 are $$3.25$$, $$3.5$$, and $$3.75$$.
4. Nikhitha says median of 2x, 5x, 3x, x² is 15 and x=6.
- Arrange numbers in increasing order for median.
- For x=6: values are 2*6=12, 5*6=30, 3*6=18, and $$6^2=36$$.
- Sort: 12, 18, 30, 36.
- Median of 4 numbers is average of 2nd and 3rd terms: $$\frac{18 + 30}{2} = 24$$, not 15.
- So Nikhitha is incorrect because with x=6 median is 24, not 15.
5. Ratio of complementary angles is 2:3, find angles.
- Complementary angles sum to 90°.
- Let angles be $$2k$$ and $$3k$$.
- Equation: $$2k + 3k = 90$$.
- $$5k = 90 \Rightarrow k=18$$.
- Angles are $$2k=36^\circ$$ and $$3k=54^\circ$$.
6. Show (6, -4) and (3, -2) satisfy $$2x + 3y = 0$$.
- For (6, -4): $$2(6) + 3(-4) = 12 - 12 = 0$$, satisfies equation.
- For (3, -2): $$2(3) + 3(-2) = 6 - 6 = 0$$, satisfies equation.
Final answers included in steps.