Ratio Problems 0149Bb
1. **Problem 6:** At a certain school, \(\frac{1}{4}\) of the teachers are women. Find the ratio of the number of male teachers to female teachers.
- Total teachers = 1 (consider as whole)
- Female teachers = \(\frac{1}{4}\)
- Male teachers = \(1 - \frac{1}{4} = \frac{3}{4}\)
- Ratio male to female = \(\frac{3}{4} : \frac{1}{4} = 3 : 1\)
2. **Problem 7:** Sana cleaned \(4 \frac{1}{6}\) of her house, and her sister cleaned \(5 \frac{1}{5}\) of the remaining. Find the ratio of clean to unclean.
- Convert mixed numbers to improper fractions:
- Sana cleaned: \(4 \frac{1}{6} = \frac{25}{6}\)
- Sister cleaned: \(5 \frac{1}{5} = \frac{26}{5}\)
- Total cleaned = Sana + Sister = \(\frac{25}{6} + \frac{26}{5} = \frac{125}{30} + \frac{156}{30} = \frac{281}{30}\)
- Since total house is 1, unclean = \(1 - \frac{281}{30} = \frac{30}{30} - \frac{281}{30} = -\frac{251}{30}\) (negative means problem data inconsistent or interpreted incorrectly; assuming question means parts cleaned out of total 10 parts, ratio clean to unclean = \(\frac{25}{6} + \frac{26}{5} : \text{remaining}\) is ambiguous, so we skip this or clarify.)
3. **Problem 8:** Two sums of money are in the ratio 5 : 8. The smaller amount is 65. Find the larger amount.
- Ratio: 5 : 8
- Smaller amount corresponds to 5 parts = 65
- One part = \(\frac{65}{5} = 13\)
- Larger amount = 8 parts = \(8 \times 13 = 104\)
4. **Problem 9:** The weight of 15 feet of wire is 6 pounds. How many pounds will 25 feet of the same wire weigh?
- Weight per foot = \(\frac{6}{15} = 0.4\) pounds
- Weight of 25 feet = \(25 \times 0.4 = 10\) pounds
5. **Problem 10:** 16 boys can dig a ditch in 8 hours. How many hours would it take 10 boys working at the same rate?
- Work done = boys \(\times\) hours = constant
- For 16 boys: \(16 \times 8 = 128\) boy-hours
- For 10 boys: hours = \(\frac{128}{10} = 12.8\) hours
Final answers:
- Problem 6: Ratio male to female = \(3 : 1\)
- Problem 8: Larger amount = 104
- Problem 9: Weight of 25 feet = 10 pounds
- Problem 10: Time for 10 boys = 12.8 hours
Note: Problem 7 data is ambiguous and skipped.