Rate Problem Dc0Cac
1. **Problem Statement:** An airplane travels 1400 km in the same time a car travels 560 km. The car's speed is 200 kph less than the airplane's speed. Find the rate of each vehicle.
2. **Step 1: Understand the Problem**
- We need to find the speeds (rates) of the airplane and the car.
- The airplane travels 1400 km, the car 560 km, both in the same time.
- The car's speed is 200 kph less than the airplane's speed.
3. **Step 2: Devise a Plan**
- Use the formula for time: $$\text{time} = \frac{\text{distance}}{\text{speed}}$$
- Let the airplane's speed be $x$ kph.
- Then the car's speed is $x - 200$ kph.
- Since time is the same for both, set their times equal:
$$\frac{1400}{x} = \frac{560}{x - 200}$$
4. **Step 3: Carry Out the Plan**
- Cross multiply:
$$1400(x - 200) = 560x$$
- Expand:
$$1400x - 280000 = 560x$$
- Bring terms to one side:
$$1400x - 560x = 280000$$
$$840x = 280000$$
- Solve for $x$:
$$x = \frac{280000}{840} = 333.33$$
- So, airplane speed $= 333.33$ kph.
- Car speed $= 333.33 - 200 = 133.33$ kph.
5. **Step 4: Look Back and Reflect**
- Check times:
- Airplane time: $$\frac{1400}{333.33} \approx 4.2 \text{ hours}$$
- Car time: $$\frac{560}{133.33} \approx 4.2 \text{ hours}$$
- Times match, solution is consistent.
**Final Answer:**
- Airplane speed is approximately $333.33$ kph.
- Car speed is approximately $133.33$ kph.