1. The problem asks which form of the quadratic function $h$ displays the zeros of the function. 2. The zeros of a quadratic function are the values of $x$ for which $h(x) = 0$. 3. The factored form of a quadratic function explicitly shows the zeros as the values that make each factor zero. 4. Let's analyze each option: - A. $h(x) = -2(2x^2 - 8)$ is factored partially but not fully factored to show zeros. - B. $h(x) = -4(x^2 - 4)$ is factored partially but $x^2 - 4$ can be factored further. - C. $h(x) = -4x^2 + 16$ is in standard form, no zeros shown. - D. $h(x) = -4(x - 2)(x + 2)$ is fully factored, showing zeros at $x=2$ and $x=-2$. 5. Therefore, the form that displays the zeros is option D. Final answer: D. $h(x) = -4(x - 2)(x + 2)$