1. The problem is to find the zero(s) of the quadratic polynomial $$p(x)=x^2+7\times100$$. 2. First, simplify the polynomial: $$p(x)=x^2+700$$ 3. To find the zero(s), set the polynomial equal to zero and solve for $x$: $$x^2+700=0$$ 4. Move the constant term to the right side: $$x^2=-700$$ 5. Take the square root of both sides: $$x=\pm\sqrt{-700}$$ 6. Since the square root of a negative number involves imaginary numbers, write: $$x=\pm\sqrt{700}i$$ 7. Simplify $$\sqrt{700}$$: $$\sqrt{700}=\sqrt{7\times100}=10\sqrt{7}$$ 8. Thus, the solutions (zeros) are: $$x=\pm 10\sqrt{7}i$$ Final answer: $$x=\pm 10\sqrt{7}i$$