1. **Problem Statement:** Find the quadratic relation given that the x-intercepts are 0 and 5. 2. **Formula and Explanation:** A quadratic relation with x-intercepts $r_1$ and $r_2$ can be written as: $$y = a(x - r_1)(x - r_2)$$ where $a$ is a nonzero constant that affects the parabola's width and direction. 3. **Apply the given intercepts:** Here, $r_1 = 0$ and $r_2 = 5$, so: $$y = a(x - 0)(x - 5) = a x (x - 5)$$ 4. **Simplify the expression:** $$y = a(x^2 - 5x)$$ 5. **Interpretation:** Without additional information, the simplest form assumes $a = 1$: $$y = x^2 - 5x$$ This quadratic relation has x-intercepts at 0 and 5 as required.