Subjects algebra

Quadratic Solve F3A56C

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Quadratic Solve F3A56C


1. **State the problem:** Solve the quadratic equation $10147x^2 - 624.5x - 1 = 0$ for $x$. 2. **Formula used:** The quadratic formula is used to solve equations of the form $ax^2 + bx + c = 0$: $$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$ where $a = 10147$, $b = -624.5$, and $c = -1$. 3. **Calculate the discriminant:** $$\Delta = b^2 - 4ac = (-624.5)^2 - 4 \times 10147 \times (-1)$$ $$= 390000.25 + 40588 = 430588.25$$ 4. **Find the square root of the discriminant:** $$\sqrt{430588.25} \approx 656.28$$ 5. **Apply the quadratic formula:** $$x = \frac{-(-624.5) \pm 656.28}{2 \times 10147} = \frac{624.5 \pm 656.28}{20294}$$ 6. **Calculate the two solutions:** - For the plus sign: $$x_1 = \frac{624.5 + 656.28}{20294} = \frac{1280.78}{20294} \approx 0.0631$$ - For the minus sign: $$x_2 = \frac{624.5 - 656.28}{20294} = \frac{-31.78}{20294} \approx -0.00157$$ **Final answer:** $$x \approx 0.0631 \text{ or } x \approx -0.00157$$