1. The given expression is a quadratic polynomial: $x^2+3x-3$. 2. To understand it better, we can find its roots by solving $x^2+3x-3=0$ using the quadratic formula: $$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$ where $a=1$, $b=3$, and $c=-3$. 3. Calculate the discriminant: $$\Delta=b^2-4ac=3^2-4(1)(-3)=9+12=21$$ 4. Find roots: $$x=\frac{-3\pm\sqrt{21}}{2}$$ 5. Therefore, the polynomial factors as: $$x^2+3x-3=\left(x-\frac{-3+\sqrt{21}}{2}\right)\left(x-\frac{-3-\sqrt{21}}{2}\right)$$ This shows the roots and factorization of the quadratic expression clearly.