Quadratic Numbers
1. Problem 7: If four times a whole number is subtracted from three times the square of the number, the result 15 is obtained. Find the number.
Step 1: Let the whole number be $x$.
Step 2: Form the equation from the problem statement: $$3x^2 - 4x = 15$$
Step 3: Rearrange to standard quadratic form: $$3x^2 - 4x - 15 = 0$$
Step 4: Use the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, here $a=3$, $b=-4$, $c=-15$.
Step 5: Calculate the discriminant: $$\Delta = (-4)^2 - 4 \times 3 \times (-15) = 16 + 180 = 196$$
Step 6: Calculate roots: $$x = \frac{4 \pm \sqrt{196}}{2 \times 3} = \frac{4 \pm 14}{6}$$
Step 7: Possible values:
- $x = \frac{4 + 14}{6} = \frac{18}{6} = 3$
- $x = \frac{4 - 14}{6} = \frac{-10}{6} = -\frac{5}{3}$ (not a whole number)
Answer: The number is 3.
2. Problem 8: Two consecutive positive numbers are such that the sum of their squares is 113. Find the two numbers.
Step 1: Let the numbers be $x$ and $x+1$ (consecutive integers).
Step 2: Write equation for sum of squares:
$$x^2 + (x+1)^2 = 113$$
Step 3: Expand:
$$x^2 + x^2 + 2x + 1 = 113$$
Step 4: Simplify:
$$2x^2 + 2x + 1 = 113$$
Step 5: Rearrange:
$$2x^2 + 2x + 1 - 113 = 0$$
$$2x^2 + 2x - 112 = 0$$
Step 6: Divide whole equation by 2:
$$x^2 + x - 56 = 0$$
Step 7: Factor quadratic:
$$(x + 8)(x - 7) = 0$$
Step 8: Solutions:
- $x = -8$ (not positive)
- $x = 7$ (positive)
Step 9: Numbers are 7 and 8.
Answer: The two numbers are 7 and 8.
3. Problem 9: The difference between two positive numbers is 7 and the square of their sum is 289. Find the two numbers.
Step 1: Let the two numbers be $x$ and $y$ with $x > y$.
Step 2: From the problem:
$$x - y = 7$$
$$ (x + y)^2 = 289 $$
Step 3: Solve for $x$ from the first: $x = y + 7$
Step 4: Substitute into the second:
$$ (y + 7 + y)^2 = 289 $$
$$ (2y + 7)^2 = 289 $$
Step 5: Take square root:
$$ 2y + 7 = \pm 17 $$
Step 6: Consider $2y + 7 = 17$
$$ 2y = 10 \, \Rightarrow \, y=5 $$
Step 7: Calculate $x$:
$$ x = 5 + 7 = 12 $$
Step 8: Check $2y + 7 = -17$
$$ 2y = -24 \, \Rightarrow \, y = -12 $$ (not positive, discard)
Answer: The two numbers are 12 and 5.