1. **State the problem:** Find the coordinates where the graph of the quadratic equation $$y = (4 - x)(x + 5)$$ crosses the x-axis and y-axis. 2. **Find x-intercepts:** The graph crosses the x-axis where $$y = 0$$. Set $$y = 0$$: $$0 = (4 - x)(x + 5)$$ This product is zero if either factor is zero: - $$4 - x = 0 \Rightarrow x = 4$$ - $$x + 5 = 0 \Rightarrow x = -5$$ So the x-intercepts are at points: - $$(4, 0)$$ - $$(-5, 0)$$ 3. **Find y-intercept:** The graph crosses the y-axis where $$x = 0$$. Substitute $$x = 0$$ into the equation: $$y = (4 - 0)(0 + 5) = 4 \times 5 = 20$$ So the y-intercept is at point: - $$(0, 20)$$ **Final answer:** - x-intercepts: $$(4, 0)$$ and $$(-5, 0)$$ - y-intercept: $$(0, 20)$$