1. The problem is to solve a quadratic equation using the grade 10 quadratic formula. 2. The quadratic formula is given by $$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$ where $a$, $b$, and $c$ are coefficients from the quadratic equation $ax^2+bx+c=0$. 3. Important rules: - Calculate the discriminant $\Delta = b^2 - 4ac$. - If $\Delta > 0$, there are two real and distinct solutions. - If $\Delta = 0$, there is one real solution. - If $\Delta < 0$, there are no real solutions (complex solutions). 4. Substitute the values of $a$, $b$, and $c$ into the formula. 5. Simplify under the square root and calculate the two possible values for $x$. 6. This method works for any quadratic equation and is a standard approach taught in grade 10 algebra. Since no specific quadratic equation was provided, this is the general method to solve any quadratic using the grade 10 quadratic formula.