1. The problem is to find the value of the function $y = 2x^2 - 3x + 5$ when $x = 4$. 2. The formula given is a quadratic function: $$y = 2x^2 - 3x + 5$$ where $x$ is the input variable and $y$ is the output. 3. To find $y$ at $x=4$, substitute $4$ into the equation: $$y = 2(4)^2 - 3(4) + 5$$ 4. Calculate the powers and products: $$y = 2 \times 16 - 12 + 5$$ 5. Simplify step-by-step: $$y = 32 - 12 + 5$$ $$y = 20 + 5$$ $$y = 25$$ 6. Therefore, the value of the function at $x=4$ is $25$.