Quadratic Analysis 41D86B
1. **State the problem:**
We are given the quadratic expression $2x^2 - 5x + 2$ and want to analyze it.
2. **Formula and rules:**
A quadratic expression is generally written as $ax^2 + bx + c$.
Here, $a=2$, $b=-5$, and $c=2$.
3. **Find the roots using the quadratic formula:**
$$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$
4. **Calculate the discriminant:**
$$\Delta = b^2 - 4ac = (-5)^2 - 4 \times 2 \times 2 = 25 - 16 = 9$$
5. **Calculate the roots:**
$$x = \frac{-(-5) \pm \sqrt{9}}{2 \times 2} = \frac{5 \pm 3}{4}$$
6. **Evaluate each root:**
- For $+$ sign: $x = \frac{5 + 3}{4} = \frac{8}{4} = 2$
- For $-$ sign: $x = \frac{5 - 3}{4} = \frac{2}{4} = 0.5$
7. **Vertex of the parabola:**
The vertex $x$-coordinate is given by $x = -\frac{b}{2a} = -\frac{-5}{2 \times 2} = \frac{5}{4} = 1.25$
8. **Calculate the vertex $y$-coordinate:**
$$y = 2(1.25)^2 - 5(1.25) + 2 = 2(1.5625) - 6.25 + 2 = 3.125 - 6.25 + 2 = -1.125$$
9. **Summary:**
- Roots: $x=2$ and $x=0.5$
- Vertex: $(1.25, -1.125)$
- Since $a=2 > 0$, the parabola opens upwards.
This completes the analysis of the quadratic $2x^2 - 5x + 2$.