Subjects algebra

Profit Rate 4Fc5C5

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Profit Rate 4Fc5C5


1. **State the problem:** We need to find Jada's rate of change (slope) of her weekly profit as a function of the amount of paprika sold. 2. **Recall the formula for slope:** The slope $m$ of a line passing through two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ This slope represents the rate of change of profit per kilogram of paprika sold. 3. **Identify the points from the graph:** The line passes through $(-20, -200)$ and $(100, 500)$. 4. **Calculate the slope:** $$m = \frac{500 - (-200)}{100 - (-20)} = \frac{500 + 200}{100 + 20} = \frac{700}{120} = \frac{35}{6} \approx 5.83$$ 5. **Interpretation:** Jada's rate of change is approximately $5.83$ dollars per kilogram. This means for each additional kilogram of paprika sold, her profit increases by about $5.83$ dollars. **Final answer:** Jada's rate is $\boxed{\frac{35}{6}}$ or approximately $5.83$ dollars per kilogram.