Polynomial Multiplication 3B9A7F
1. **State the problem:** Simplify the expression $$(4s-4)(-s^2 + 3s + 1)$$.
2. **Recall the distributive property:** To multiply two polynomials, multiply each term in the first polynomial by each term in the second polynomial.
3. **Factor out common terms if possible:** Notice $4s - 4 = 4(s - 1)$, which might simplify multiplication.
4. **Multiply:**
$$4(s - 1)(-s^2 + 3s + 1) = 4 \times (s - 1) \times (-s^2 + 3s + 1)$$
5. **First multiply $(s - 1)$ and $(-s^2 + 3s + 1)$:**
$$s \times (-s^2 + 3s + 1) = -s^3 + 3s^2 + s$$
$$-1 \times (-s^2 + 3s + 1) = s^2 - 3s - 1$$
6. **Add the results:**
$$(-s^3 + 3s^2 + s) + (s^2 - 3s - 1) = -s^3 + 4s^2 - 2s - 1$$
7. **Multiply by 4:**
$$4 \times (-s^3 + 4s^2 - 2s - 1) = -4s^3 + 16s^2 - 8s - 4$$
**Final answer:**
$$-4s^3 + 16s^2 - 8s - 4$$