1. The problem is to evaluate the polynomial $2,353x^3 + 44,998x$ for the values $x=0, 1, 2, 3, 3.4$. 2. The formula is given as $f(x) = 2,353x^3 + 44,998x$. 3. We will substitute each value of $x$ into the formula and calculate the result step-by-step. 4. For $x=0$: $$f(0) = 2,353 \times 0^3 + 44,998 \times 0 = 0 + 0 = 0$$ 5. For $x=1$: $$f(1) = 2,353 \times 1^3 + 44,998 \times 1 = 2,353 + 44,998 = 47,351$$ 6. For $x=2$: $$f(2) = 2,353 \times 2^3 + 44,998 \times 2 = 2,353 \times 8 + 44,998 \times 2 = 18,824 + 89,996 = 108,820$$ 7. For $x=3$: $$f(3) = 2,353 \times 3^3 + 44,998 \times 3 = 2,353 \times 27 + 44,998 \times 3 = 63,531 + 134,994 = 198,525$$ 8. For $x=3.4$: $$f(3.4) = 2,353 \times (3.4)^3 + 44,998 \times 3.4$$ Calculate $3.4^3 = 3.4 \times 3.4 \times 3.4 = 39.304$. $$f(3.4) = 2,353 \times 39.304 + 44,998 \times 3.4 = 92,429.312 + 152,993.2 = 245,422.512$$ Final answers: - $f(0) = 0$ - $f(1) = 47,351$ - $f(2) = 108,820$ - $f(3) = 198,525$ - $f(3.4) \approx 245,422.512$