Polygon Perimeter
1. The problem states an irregular polygon with sides labeled as $x-2$, $x$, $x-7$, $x-1$, and $x-3$, and the total perimeter is 52 inches.
2. To find $x$, we set up an equation: the sum of all side lengths equals the perimeter.
$$ (x-2) + x + (x-7) + (x-1) + (x-3) = 52 $$
3. Combine like terms:
$$ x - 2 + x + x - 7 + x - 1 + x - 3 = 52 $$
$$ 5x - (2 + 7 + 1 + 3) = 52 $$
$$ 5x - 13 = 52 $$
4. Solve for $x$:
$$ 5x = 52 + 13 $$
$$ 5x = 65 $$
$$ x = \frac{65}{5} = 13 $$
5. Check that all sides are positive using $x=13$:
- $13 - 2 = 11$
- $13$
- $13 - 7 = 6$
- $13 - 1 = 12$
- $13 - 3 = 10$
All are positive.
6. Final answer:
$$ \boxed{13} $$