Piecewise Graph D0D629
1. The problem is to analyze and graph the piecewise function:
$$Y = \begin{cases} -2x^2 + x - 5 & \text{if } x < -2 \\ |x - 4| & \text{if } x \geq 2 \end{cases}$$
2. First, solve for the roots of the quadratic part $-2x^2 + x - 5 = 0$ to find intercepts.
3. Use the quadratic formula: $$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$ where $a = -2$, $b = 1$, $c = -5$.
4. Calculate the discriminant: $$\Delta = b^2 - 4ac = 1^2 - 4(-2)(-5) = 1 - 40 = -39$$
5. Since $\Delta < 0$, there are no real roots; the parabola does not cross the x-axis.
6. For $x \geq 2$, the function is $y = |x - 4|$, which is a V-shaped graph with vertex at $(4,0)$.
7. The graph has two parts:
- For $x < -2$, a downward opening parabola $-2x^2 + x - 5$ with vertex and no x-intercepts.
- For $x \geq 2$, the absolute value function $|x - 4|$.
8. The graph is undefined between $-2$ and $2$.
Final answer: The piecewise function consists of a parabola on the left side and an absolute value function on the right side, with no x-intercepts for the parabola and a vertex at $(4,0)$ for the absolute value part.