1. The problem asks for the equation of a line that passes through the point $(0,3)$ and is perpendicular to the line given by $$y = -x + 1.$$\n\n2. The slope of the given line is $-1$ because it is in the form $y = mx + b$ where $m$ is the slope.\n\n3. Lines that are perpendicular have slopes that are negative reciprocals. The negative reciprocal of $-1$ is $1$. So, the slope of the line we want is $1$.\n\n4. Use the point-slope form of a line equation: $$y - y_1 = m(x - x_1)$$ where $(x_1, y_1)$ is the point $(0,3)$ and $m=1$.\n\n5. Substitute the values: $$y - 3 = 1(x - 0)$$ which simplifies to $$y - 3 = x.$$\n\n6. Rearranging to standard form: $$y - x = 3$$ or equivalently $$-x + y = 3.$$\n\n7. Comparing with the options, the correct equation is option d: $$-x + y = 3.$$