Permutation 20P3 0Ff8A2
1. **Problem:** Calculate the value of $20P_3$.
2. **Formula:** The permutation formula is given by
$$nP_r = \frac{n!}{(n-r)!}$$
where $n$ is the total number of items, and $r$ is the number of items to arrange.
3. **Apply the formula:**
$$20P_3 = \frac{20!}{(20-3)!} = \frac{20!}{17!}$$
4. **Simplify factorials:**
$$\frac{20!}{17!} = 20 \times 19 \times 18$$
5. **Calculate the product:**
$$20 \times 19 = 380$$
$$380 \times 18 = 6840$$
6. **Answer:**
$$20P_3 = 6840$$
This means there are 6840 ways to arrange 3 items out of 20 in order.