Paul Alone
1. **State the problem:** Sam, Ton, and Paul together can finish a job in 3 hours. Sam alone can finish in 6 hours, and Ton alone in 8 hours. We need to find how long Paul alone will take to finish the job.
2. **Define rates:** The rate of work is \( \text{work done per hour} \).
- Sam's rate: \( \frac{1}{6} \) (job/hour)
- Ton's rate: \( \frac{1}{8} \) (job/hour)
- Combined rate of Sam, Ton, and Paul: \( \frac{1}{3} \) (job/hour)
3. **Set up equation:** Let Paul's rate be \( \frac{1}{p} \) (job/hour).
The sum of their rates is:
$$
\frac{1}{6} + \frac{1}{8} + \frac{1}{p} = \frac{1}{3}
$$
4. **Solve for \( \frac{1}{p} \):**
Calculate \( \frac{1}{6} + \frac{1}{8} \) first:
$$
\frac{1}{6} = \frac{4}{24}, \quad \frac{1}{8} = \frac{3}{24} \implies \frac{1}{6} + \frac{1}{8} = \frac{4}{24} + \frac{3}{24} = \frac{7}{24}
$$
Therefore:
$$
\frac{7}{24} + \frac{1}{p} = \frac{1}{3}
$$
Subtract \( \frac{7}{24} \) from both sides:
$$
\frac{1}{p} = \frac{1}{3} - \frac{7}{24} = \frac{8}{24} - \frac{7}{24} = \frac{1}{24}
$$
5. **Find \( p \):**
$$
p = 24
$$
**Answer:** Paul alone can finish the job in 24 hours.