1. The problem asks which graph has a slope that best represents the rate of $8$ per car for parking. 2. The slope of a line represents the rate of change, calculated as $\text{slope} = \frac{\text{change in cost}}{\text{change in number of cars}}$. 3. Since the parking lot charges $8$ per car, the slope should be $8$. 4. Let's analyze each graph's slope: - Graph a: The cost increases from about $1$ to $10$ when the number of cars increases from $1$ to $2$. Slope $= \frac{10-1}{2-1} = 9$ (close to $8$). - Graph b: The cost increases from $1$ to $9$ when the number of cars increases from $1$ to $9$. Slope $= \frac{9-1}{9-1} = 1$ (too low). - Graph c: The cost increases from $1$ to $2$ when the number of cars increases from $1$ to $9$. Slope $= \frac{2-1}{9-1} = \frac{1}{8} = 0.125$ (too low). - Graph d: The cost is constant at about $9$ regardless of the number of cars. Slope $= 0$ (no change). 5. The slope closest to $8$ is from Graph a. **Final answer:** Graph a best represents the rate of $8$ per car.