1. The problem asks to find the equation of line B, which passes through point P and is parallel to line A. 2. First, determine the slope of line A. It passes through (0,0) and (1,2). 3. Calculate the slope $m$ of line A using the formula: $$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{2 - 0}{1 - 0} = 2$$ 4. Since line B is parallel to line A, its slope is the same, $m = 2$. 5. Line B passes through point P, which is approximately at (1,6). 6. Use the point-slope form to find the equation of line B: $$y - y_1 = m(x - x_1)$$ Substitute $m=2$, $x_1=1$, and $y_1=6$: $$y - 6 = 2(x - 1)$$ 7. Simplify to slope-intercept form $y = mx + c$: $$y - 6 = 2x - 2$$ $$y = 2x - 2 + 6$$ $$y = 2x + 4$$ Final answer: $$\boxed{y = 2x + 4}$$