1. The problem asks for the range of the function represented by the graph. 2. The graph is a parabola opening upwards with its vertex at approximately $(0,1)$. 3. For a parabola $y = a(x-h)^2 + k$ opening upwards, the vertex $(h,k)$ is the minimum point. 4. Since the vertex is at $(0,1)$ and the parabola opens upwards, the minimum value of $y$ is $1$. 5. Therefore, the range of the function is all $y$ values such that $y \geq 1$. 6. This corresponds to option A: $y \geq 1$. Final answer: $\boxed{y \geq 1}$