1. **Problem Statement:** A sheet of paper is folded exactly in half once, resulting in 2 equal parts. Then it is folded a second time, resulting in 4 equal parts, and so on. How many parts are obtained if the paper is folded 10 times? 2. **Formula Used:** Each fold doubles the number of parts. After $n$ folds, the number of parts is given by: $$\text{Number of parts} = 2^n$$ 3. **Explanation:** - After 1 fold, parts = $2^1 = 2$ - After 2 folds, parts = $2^2 = 4$ - This pattern continues, doubling each time. 4. **Calculation:** For 10 folds: $$2^{10} = 1024$$ 5. **Answer:** The number of parts after 10 folds is $1024$. Therefore, the correct choice is B. 1024.