P Cube Sum
1. Problem: Given $p + \frac{1}{p} = 5$, find the value of $p^3 + \frac{1}{p^3}$.
2. Start with the identity: $$\left(p + \frac{1}{p}\right)^3 = p^3 + \frac{1}{p^3} + 3\left(p + \frac{1}{p}\right)$$
3. Substitute $p + \frac{1}{p} = 5$ into the equation:
$$5^3 = p^3 + \frac{1}{p^3} + 3 \times 5$$
4. Simplify the left side:
$$125 = p^3 + \frac{1}{p^3} + 15$$
5. Solve for $p^3 + \frac{1}{p^3}$:
$$p^3 + \frac{1}{p^3} = 125 - 15 = 110$$
Final answer: $110$