1. The problem states: Multiply both sides by $x$ given the equation $y = - \frac{1}{\sqrt{3}} x$. 2. The equation is already expressed as $y = - \frac{1}{\sqrt{3}} x$, which means $y$ equals $- \frac{1}{\sqrt{3}}$ times $x$. 3. Multiplying both sides by $x$ in the original equation (if we consider $y = - \frac{1}{\sqrt{3}} x$) effectively means we want to write $y x = - \frac{1}{\sqrt{3}} x^2$. 4. But since the original equation already shows $y$ in terms of $x$, the relationship is linear with slope $- \frac{1}{\sqrt{3}}$. 5. Hence, the equation after multiplying both sides by $x$ is: $$ y x = - \frac{1}{\sqrt{3}} x^2 $$ Final answer: $$ y x = - \frac{1}{\sqrt{3}} x^2 $$