1. The problem is to find the missing numbers in the multiplication expansion of $23 \times 102$ using the distributive property. 2. The distributive property states that $a \times (b + c) = a \times b + a \times c$. 3. Applying this to $23 \times 102$, we write: $$23 \times 102 = 23 \times (100 + 2)$$ 4. Distribute $23$ over the sum: $$= 23 \times 100 + 23 \times 2$$ 5. Calculate each term: $$23 \times 100 = 2300$$ $$23 \times 2 = 46$$ 6. Add the results: $$2300 + 46 = 2346$$ So the missing numbers in the boxes are: - First box: 2 - Second box: 46 - Third box: 2300 - Fourth box: 46 Final answer: $$23 \times 102 = 23 \times (100 + 2) = 23 \times 100 + 23 \times 2 = 2300 + 46 = 2346$$