Minimum Radius
1. **Minimize area of a closed cylinder with volume 250\pi ml**
Given volume $V = 250\pi$, volume formula: $$V = \pi r^2 h = 250\pi \implies r^2 h = 250$$
Surface area $A$ (including top and bottom) is: $$A = 2\pi r^2 + 2\pi r h$$
Express $h$: $$h = \frac{250}{r^2}$$
Rewrite $A$: $$A = 2\pi r^2 + 2\pi r \cdot \frac{250}{r^2} = 2\pi r^2 + \frac{500\pi}{r}$$
2. **Minimize $A$ by differentiation**
$$\frac{dA}{dr} = 4\pi r - \frac{500\pi}{r^2} = 0$$
Multiply both sides by $r^2$: $$4\pi r^3 = 500\pi$$
Divide both sides by $4\pi$: $$r^3 = \frac{500}{4} = 125$$
3. **Solve for radius $r$**
$$r = \sqrt[3]{125} = 5$$
Answer: The radius should be $5$ ml.
4. **Solve the system:**
$\frac{x+y}{3} - \frac{x-y}{4} = \frac{2}{3}$
Multiply by 12 (common denominator):
$$4(x+y) - 3(x-y) = 8$$
$$4x + 4y - 3x + 3y = 8$$
$$x + 7y = 8$$ (1)
$\frac{2x-3}{3} - \frac{2y+3}{4} = \frac{19}{2}$
Multiply by 12:
$$4(2x-3) - 3(2y+3) = 114$$
$$8x - 12 - 6y - 9 = 114$$
$$8x - 6y - 21 = 114$$
$$8x - 6y = 135$$ (2)
5. **Solve system (1) and (2):**
From (1): $$x = 8 - 7y$$
Substitute into (2):
$$8(8 - 7y) - 6y = 135$$
$$64 - 56y - 6y = 135$$
$$64 - 62y = 135$$
$$-62y = 71$$
$$y = -\frac{71}{62}$$
Calculate $x$:
$$x = 8 - 7 \times \left(-\frac{71}{62}\right) = 8 + \frac{497}{62} = \frac{496}{62} + \frac{497}{62} = \frac{993}{62}$$
Answer: $$x = \frac{993}{62}, y = -\frac{71}{62}$$
6. **Club members contribution problem:**
Let number of members be $n$.
Original contribution each: $$\frac{480000}{n}$$
Four members withdrew; remaining members = $n - 4$.
Each remaining member pays $$\frac{480000}{n} + 20000$$
Equation:
$$(n - 4) \left( \frac{480000}{n} + 20000 \right) = 480000$$
Expand:
$$(n - 4) \frac{480000}{n} + 20000(n - 4) = 480000$$
$$480000 - \frac{1920000}{n} + 20000n - 80000 = 480000$$
Simplify:
$$400000 + 20000n - \frac{1920000}{n} = 480000$$
Subtract 480000 both sides:
$$20000n - \frac{1920000}{n} = 80000$$
Multiply by $n$:
$$20000 n^2 - 1920000 = 80000 n$$
Rearranged:
$$20000 n^2 - 80000 n - 1920000 = 0$$
Divide by 4000:
$$5 n^2 - 20 n - 480 = 0$$
7. **Solve quadratic:**
$$n^2 - 4 n - 96 = 0$$
Use quadratic formula:
$$n = \frac{4 \pm \sqrt{16 + 384}}{2} = \frac{4 \pm \sqrt{400}}{2} = \frac{4 \pm 20}{2}$$
Possible values:
$$n=12\ (positive)$$ or $$n = -8\ (discard)$$
Original contribution:
$$\frac{480000}{12} = 40000$$
Answer: Each member originally contributed 40000.
8. **Calculate log 50 given log 3, log 5, and log 2:**
$$\log 50 = \log (5 \times 10) = \log 5 + \log 10$$
$$\log 10 = 1$$
So:
$$\log 50 = 0.6990 + 1 = 1.6990$$
Final answers:
- Radius of tin: $5$
- $x = \frac{993}{62}$, $y = -\frac{71}{62}$
- Original contribution: $40000$
- $\log 50 = 1.6990$