Medal Proportions
1. **State the problem:** Two teams competed for medals: Southwell Sports and Fenley Athletics. Each team's medals are shown in pie charts with angles for Bronze, Silver, and Gold medals. The total medals won are 75 for Southwell Sports and 120 for Fenley Athletics.
2. **Calculate the proportion of gold medals (angle divided by total circle angle 360°) for each team:**
- Southwell Sports gold segment: 192°
- Fenley Athletics gold segment: 180°
Proportion for Southwell Sports gold medals:
$$\frac{192}{360} = 0.5333$$ (53.33%)
Proportion for Fenley Athletics gold medals:
$$\frac{180}{360} = 0.5$$ (50%)
3. **Compare which team won a higher proportion of gold medals:**
Southwell Sports has 53.33% gold medals, which is more than Fenley Athletics' 50%. So, Southwell Sports won the higher proportion of gold medals.
4. **Calculate the number of gold medals each team won by multiplying their total medals by the gold proportion:**
- Southwell Sports gold medals:
$$75 \times 0.5333 = 40$$ (approximately)
- Fenley Athletics gold medals:
$$120 \times 0.5 = 60$$
5. **Answer:**
- a) Southwell Sports won the higher proportion of gold medals.
- b) Southwell Sports won about 40 gold medals, Fenley Athletics won 60 gold medals.