1. The problem is to multiply two matrices and simplify the result. 2. The first matrix is $$\begin{bmatrix}-2 & 0 & 5\\ -1 & 3 & 6\\ 0 & 1 & -1\end{bmatrix}$$ and the second matrix is $$\begin{bmatrix}-2 & 0\\ -1 & 3\\ 0 & 1\end{bmatrix}$$. 3. Multiply corresponding elements row-wise and column-wise to get a new matrix or scalar. 4. The multiplication is represented as $(6 + 0 + (-5)) (0 + (-12) + 0)$ which simplifies to $(1)(-12) = -12$ directly provided, but the user states $= 1 + 12 = 13$. 5. Let's verify the calculation: - For the first row of the first matrix and first column of the second matrix: $$(-2)(-2) + (0)(-1) + (5)(0) = 4 + 0 + 0 = 4$$. - For the first row of the first matrix and second column of the second matrix: $$( -2)(0) + (0)(3) + (5)(1) = 0 + 0 + 5 = 5$$. - For the second row and first column: $$(-1)(-2) + (3)(-1) + (6)(0) = 2 - 3 + 0 = -1$$. - For the second row and second column: $$(-1)(0) + (3)(3) + (6)(1) = 0 + 9 + 6 = 15$$. - For the third row and first column: $$(0)(-2) + (1)(-1) + (-1)(0) = 0 - 1 + 0 = -1$$. - For the third row and second column: $$(0)(0) + (1)(3) + (-1)(1) = 0 + 3 - 1 = 2$$. 6. So the resulting matrix is $$\begin{bmatrix}4 & 5\\ -1 & 15\\ -1 & 2\end{bmatrix}$$. 7. If the problem intends to sum the results $6+0+(-5)$ and $0 + (-12) + 0$ for some reason, it yields $(1)(-12) = -12$. 8. However, concern is the user's given simplified answer $1 + 12 = 13$ which seems to add absolute values. 9. For clarity, the direct multiplication yields the matrix above and not a scalar 13. Final answer: The matrix product is $$\begin{bmatrix}4 & 5\\ -1 & 15\\ -1 & 2\end{bmatrix}$$.