1. We are given the equation \( \frac{b}{3} + \frac{3c}{4} = 2a \) and need to make \(b\) the subject. 2. Start by isolating the term with \(b\) on one side. Subtract \( \frac{3c}{4} \) from both sides: $$ \frac{b}{3} = 2a - \frac{3c}{4} $$ 3. To solve for \(b\), multiply both sides by 3 (the denominator of \(b/3\)): $$ b = 3 \left( 2a - \frac{3c}{4} \right) $$ 4. Distribute the 3 inside the parentheses: $$ b = 3 \times 2a - 3 \times \frac{3c}{4} = 6a - \frac{9c}{4} $$ 5. The final expression with \(b\) as the subject is: $$ b = 6a - \frac{9c}{4} $$