1. The problem states that we have two logarithmic expressions with the same base $p$: $$\log_p(x) = 9$$ and $$\log_p(y) = 6$$. 2. Recall that $$\log_p(a) = b$$ means that $$p^b = a$$. 3. Using this property, rewrite the given logarithmic equations in exponential form: $$x = p^9$$ and $$y = p^6$$. 4. If you want to find relationships such as $$xy$$, $$\frac{x}{y}$$ or $$x^y$$, use the exponential forms: - $$xy = p^9 \times p^6 = p^{9+6} = p^{15}$$ - $$\frac{x}{y} = \frac{p^9}{p^6} = p^{9-6} = p^3$$ - $$x^y = (p^9)^{p^6} = p^{9 \cdot p^6}$$ (this depends on the context if such expressions are needed). 5. Without additional questions, the main takeaway is the exponential forms of $x$ and $y$ based on $p$: $$x = p^9$$ $$y = p^6$$ Final answers: $$x = p^9, \quad y = p^6$$.