1. **Stating the problem:** Calculate the values of the logarithmic expressions: a) $4\log 35$ b) $5\log 28$ c) $16\log 49$ 2. **Understanding logarithm properties:** Recall the logarithm power rule: $$n\log a = \log a^n$$ 3. **Solving each part:** a) $4\log 35 = \log 35^4$ Calculate $35^4$: $$35^4 = (35^2)^2 = 1225^2 = 1500625$$ So, $$4\log 35 = \log 1500625$$ b) $5\log 28 = \log 28^5$ Calculate $28^5$ stepwise: $$28^2 = 784$$ $$28^3 = 28 \times 784 = 21952$$ $$28^4 = 28 \times 21952 = 614656$$ $$28^5 = 28 \times 614656 = 17210368$$ So, $$5\log 28 = \log 17210368$$ c) $16\log 49 = \log 49^{16}$ Calculate $49^{16}$ is very large, but can also be expressed using powers of 7 since $49 = 7^2$: $$49^{16} = (7^2)^{16} = 7^{32}$$ So, $$16\log 49 = \log 7^{32}$$ This is a concise way to express the result. **Final answers:** a) $4\log 35 = \log 1500625$ b) $5\log 28 = \log 17210368$ c) $16\log 49 = \log 7^{32}$