Logarithm Expression C6B41E
1. **State the problem:**
Solve for $L$ given the expression
$$L = 10 \log \left( \frac{10^{4.8} + 10^{4.6}}{10^{-12}} \right)$$
2. **Recall the logarithm properties:**
- $\log \left( \frac{a}{b} \right) = \log a - \log b$
- $\log (a + b)$ cannot be simplified directly, but we can factor or approximate.
- $\log (10^x) = x$
3. **Simplify the numerator:**
$$10^{4.8} + 10^{4.6} = 10^{4.6} (10^{0.2} + 1)$$
Calculate $10^{0.2}$:
$$10^{0.2} = 10^{\frac{1}{5}} = \sqrt[5]{10} \approx 1.5849$$
So,
$$10^{4.8} + 10^{4.6} \approx 10^{4.6} (1.5849 + 1) = 10^{4.6} \times 2.5849$$
4. **Rewrite the expression inside the log:**
$$\frac{10^{4.8} + 10^{4.6}}{10^{-12}} = \frac{10^{4.6} \times 2.5849}{10^{-12}} = 2.5849 \times 10^{4.6 + 12} = 2.5849 \times 10^{16.6}$$
5. **Apply the log:**
$$\log \left( 2.5849 \times 10^{16.6} \right) = \log 2.5849 + \log 10^{16.6} = \log 2.5849 + 16.6$$
Calculate $\log 2.5849$:
$$\log 2.5849 \approx 0.412$$
6. **Calculate $L$:**
$$L = 10 \times (0.412 + 16.6) = 10 \times 17.012 = 170.12$$
7. **Check the second expression:**
$$L = 10 \log (10^{2.6}) = 10 \times 2.6 = 26$$
This is different from the first calculation, so the two expressions are not equal.
**Final answer:**
$$L \approx 170.12$$