1. The problem is to evaluate the expression $K \approx 1 + 3.3 \log x(40)$. 2. Here, $\log$ typically means the base-10 logarithm. The expression suggests $x$ is a function or variable evaluated at 40, so we interpret it as $\log(40)$. 3. The formula used is: $$K \approx 1 + 3.3 \log(40)$$ 4. Calculate $\log(40)$: Since $\log(10) = 1$ and $\log(100) = 2$, $\log(40)$ is between 1 and 2. Using a calculator, $\log(40) \approx 1.60206$. 5. Substitute back: $$K \approx 1 + 3.3 \times 1.60206$$ 6. Multiply: $$3.3 \times 1.60206 = 5.2868$$ 7. Add 1: $$K \approx 1 + 5.2868 = 6.2868$$ 8. Therefore, the approximate value of $K$ is $6.29$ (rounded to two decimal places).