1. **State the problem:** Solve the equation $$-9 \log_3 -4p = -27$$ for $p$. 2. **Rewrite the equation:** The equation is $$-9 \log_3 (-4p) = -27$$. 3. **Isolate the logarithm:** Divide both sides by $-9$: $$\log_3 (-4p) = \frac{-27}{-9} = 3$$ 4. **Use the definition of logarithm:** Recall that $\log_b a = c$ means $a = b^c$. So, $$-4p = 3^3$$ 5. **Calculate the power:** $$3^3 = 27$$ 6. **Solve for $p$:** $$-4p = 27 \implies p = \frac{27}{-4} = -\frac{27}{4} = -6.75$$ **Final answer:** $$p = -6.75$$