1. We are asked to calculate the value of $$\frac{3612 \times 750.9}{113.2 \times 9.98}$$ using logarithms. 2. Recall that logarithms convert multiplication and division into addition and subtraction: $$\log \left(\frac{a \times b}{c \times d}\right) = \log a + \log b - \log c - \log d$$ 3. Calculate each logarithm (using base 10): $$\log 3612 \approx 3.5575$$ $$\log 750.9 \approx 2.8752$$ $$\log 113.2 \approx 2.0531$$ $$\log 9.98 \approx 0.9991$$ 4. Substitute into the formula: $$\log \left(\frac{3612 \times 750.9}{113.2 \times 9.98}\right) = 3.5575 + 2.8752 - 2.0531 - 0.9991 = 3.3805$$ 5. Find the antilogarithm to get the result: $$10^{3.3805} \approx 2397$$ Final answer: $$\frac{3612 \times 750.9}{113.2 \times 9.98} \approx 2397$$