Subjects algebra

Log Function Ac4C0D

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Log Function Ac4C0D


Let's solve the function step by step! 🎉 **Step 1:** Understand the function $f(x) = \log(x^2 - 4)(x^2 - x)$. **Step 2:** First, find $x^2 - 4$. Imagine you have 3 apples 🍎 🍎 🍎 in one group and 2 apples 🍎 🍎 in another group. Squaring means multiplying the number by itself. **Step 3:** Then find $x^2 - x$. This is like having a group of toys and taking some away. **Step 4:** The function means we take the log of $(x^2 - 4)$ and multiply it by $(x^2 - x)$. **Step 5:** Remember, the log works only if $x^2 - 4 > 0$. So, $x^2 > 4$, meaning $x > 2$ or $x < -2$. **Step 6:** Choose a number for $x$ that fits this rule, like $x = 3$. **Step 7:** Calculate $x^2 - 4 = 3^2 - 4 = 9 - 4 = 5$. **Step 8:** Calculate $x^2 - x = 9 - 3 = 6$. **Step 9:** Now find $f(3) = \log(5) \times 6$. **Step 10:** Great! $\log(5)$ is about 0.699, so $f(3) \approx 0.699 \times 6 = 4.194$. You did it! 🎯 Final answer: $f(3) \approx 4.194$