Linear System 8F58C1
1. **Problem statement:** Solve the system of linear equations:
$$\begin{cases} x + 2y = 4 \\ -x + 4y = 2 \end{cases}$$
2. **Formula and method:** We will use the method of addition (elimination) to solve the system. The goal is to eliminate one variable by adding the two equations.
3. **Step 1: Add the two equations**
$$ (x + 2y) + (-x + 4y) = 4 + 2 $$
Simplify:
$$ x - x + 2y + 4y = 6 $$
$$ 6y = 6 $$
4. **Step 2: Solve for $y$**
$$ y = \frac{6}{6} = 1 $$
5. **Step 3: Substitute $y=1$ into the first equation**
$$ x + 2(1) = 4 $$
$$ x + 2 = 4 $$
$$ x = 4 - 2 = 2 $$
6. **Final answer:**
$$ x = 2, \quad y = 1 $$
This means the solution to the system is the point $(2,1)$ where both equations intersect.