1. **State the problem:** Find the x-intercept and y-intercept of the linear equation $$-3x + 11y = 66$$. 2. **Recall the intercept definitions:** - The x-intercept is where the graph crosses the x-axis, so $y=0$. - The y-intercept is where the graph crosses the y-axis, so $x=0$. 3. **Find the x-intercept:** Set $y=0$ in the equation: $$-3x + 11(0) = 66 \implies -3x = 66$$ Divide both sides by $-3$: $$x = \frac{66}{-3} = -22$$ So, the x-intercept is $$(-22, 0)$$. 4. **Find the y-intercept:** Set $x=0$ in the equation: $$-3(0) + 11y = 66 \implies 11y = 66$$ Divide both sides by $11$: $$y = \frac{66}{11} = 6$$ So, the y-intercept is $$(0, 6)$$. **Final answer:** - x-intercept: $(-22, 0)$ - y-intercept: $(0, 6)$