1. **State the problem:** We are given a linear function $f(x)$ and its graph, and we want to find which equation form $f(x)$ could have, given that $c$ and $d$ are positive constants. 2. **Analyze the given graph:** The line passes through points approximately $(-3, 10.5)$ and $(2, 1.5)$. 3. **Find the slope $m$ of the line:** $$m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1.5 - 10.5}{2 - (-3)} = \frac{-9}{5} = -1.8$$ 4. **Find the y-intercept $b$ using point-slope form:** Using point $(2, 1.5)$: $$y = mx + b \Rightarrow 1.5 = (-1.8)(2) + b \Rightarrow 1.5 = -3.6 + b \Rightarrow b = 1.5 + 3.6 = 5.1$$ 5. **Write the equation of the line:** $$f(x) = -1.8x + 5.1$$ 6. **Compare with the options:** Options are of the form $f(x) = \pm d \pm cx$ with $c, d > 0$. Our slope is negative ($-1.8$), so $-cx$ fits. Our intercept is positive ($5.1$), so $+ d$ fits. Therefore, the correct form is: $$f(x) = d - cx$$ 7. **Answer:** Option B.